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DS integers-divisible

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Source: — Data Sufficiency |
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by akshatsingh » Wed Apr 23, 2008 10:11 pm
a) r is the product of 4 consecutive positive integers.

Multiples of 3 are 3,6,9,12...
any set of 4 positive integers will have a multiple of 3.

say 1,2,3,4 has 3
8,9,10,11 has 9(a multiple of 3)

Hence a) alone is sufficent

b) r < 25
It doesnt matter if r is less than 25 or not.


Hence A is the correct choice

Cheers!
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by Neo2000 » Wed Apr 23, 2008 10:19 pm
If the integer is n, 4 consecutive integers become

n n+1 n+2 n+3 and n+4

For any given number, if you consider it as a part of 4 consecutive numbers then you will always be able to divide it by 3

Hence only 1 is sufficient
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by simplyjat » Wed Apr 23, 2008 11:13 pm
As a general rule.

If a number is a product of N consecutive numbers, it would be completely divisible by all number from 1 to N.

So if a number is a product of four consecutive numbers, then the number is completely divisible by 1, 2, 3 and 4....
Last edited by simplyjat on Mon Apr 28, 2008 11:36 am, edited 1 time in total.
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by vinviper1 » Mon Apr 28, 2008 10:06 am
Thanks!
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