If b,c, and d are constants and x^2+bx+c=(x+d)^2 for all values of x,what is the value of c?
(1) d=3
(2) b=6
What could be the answer?
(1) d=3
(2) b=6
What could be the answer?
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discreet wrote:Is it D?Each statement is sufficient...
if you resolve the equation,you have
x^2 + bx +c = x^2 + d^2 + 2xd
Equating the co-efficients....you can conclude that
d^2=c,
2d=b
Using these equations it is possible to find the value of c if b or d is given 8)
So, D
dude calm down .. No personal remarks on the forum ..beny wrote:Roopachet, PLEASE stop saying "even I". By saying this, you are implying that 1.) you are retarded and 2.) The question is extremely easy. Yet, the majority of the time you respond, you get the answer incorrect. Therefore, you confirm part 1 of your implication, but your improper implication of part 2 makes people who don't understand the question feel bad.
Anyway, the answer is D because the question states "for all values of X". Therefore, 2d = b ALWAYS and d^2 = c ALWAYS. Each statement alone is sufficient.