Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

DS Help Needed!!!!

Expert replies
by Shadow » Tue Jul 10, 2007 2:58 am
If b,c, and d are constants and x^2+bx+c=(x+d)^2 for all values of x,what is the value of c?

(1) d=3
(2) b=6

What could be the answer?
Join the discussion
Source: — Data Sufficiency |

by discreet » Tue Jul 10, 2007 5:24 am
Is it D?Each statement is sufficient...

if you resolve the equation,you have

x^2 + bx +c = x^2 + d^2 + 2xd

Equating the co-efficients....you can conclude that

d^2=c,
2d=b

Using these equations it is possible to find the value of c if b or d is given 8)

So, D
Join the discussion

by highfive287 » Wed Jul 25, 2007 8:05 pm
discreet wrote:Is it D?Each statement is sufficient...

if you resolve the equation,you have

x^2 + bx +c = x^2 + d^2 + 2xd

Equating the co-efficients....you can conclude that

d^2=c,
2d=b

Using these equations it is possible to find the value of c if b or d is given 8)

So, D

How can you equate the co-efficients to get d^2 = c???

I think the answer should be C since you can only simplified the equation

as bx + c = 2 xd + d ^ 2 ( after canceling x^2) . You need to know the

value of b and d to determine c
Join the discussion

yep

by roopachet » Wed Aug 01, 2007 7:05 pm
even i think the answer is C
Join the discussion

by beny » Wed Aug 01, 2007 7:16 pm
Roopachet, PLEASE stop saying "even I". By saying this, you are implying that 1.) you are retarded and 2.) The question is extremely easy. Yet, the majority of the time you respond, you get the answer incorrect. Therefore, you confirm part 1 of your implication, but your improper implication of part 2 makes people who don't understand the question feel bad.

Anyway, the answer is D because the question states "for all values of X". Therefore, 2d = b ALWAYS and d^2 = c ALWAYS. Each statement alone is sufficient.
Join the discussion

by gabriel » Wed Aug 01, 2007 11:25 pm
beny wrote:Roopachet, PLEASE stop saying "even I". By saying this, you are implying that 1.) you are retarded and 2.) The question is extremely easy. Yet, the majority of the time you respond, you get the answer incorrect. Therefore, you confirm part 1 of your implication, but your improper implication of part 2 makes people who don't understand the question feel bad.

Anyway, the answer is D because the question states "for all values of X". Therefore, 2d = b ALWAYS and d^2 = c ALWAYS. Each statement alone is sufficient.
dude calm down .. No personal remarks on the forum ..

btw ... even I :wink: agree with D ..
Join the discussion