If x(x - 5)(x + 2) = 0, is x negative?
(1) x2 – 7x ≠ 0
(2) x2 –2x –15 ≠ 0
DS can someone explain
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From the question x = 0 or 5 or -2
Stmt 1 - x(x-7) <> 0 means x neq 0 and x neq 7 NOT SUFF
Stmt 2 - (x+3)(x-5) neq 0 means x neq -3 and x neq 5 NOT SUFF
Together x neq 0, x neq 5 so x = -2 to hold the question true. SUFF
Ans C
Stmt 1 - x(x-7) <> 0 means x neq 0 and x neq 7 NOT SUFF
Stmt 2 - (x+3)(x-5) neq 0 means x neq -3 and x neq 5 NOT SUFF
Together x neq 0, x neq 5 so x = -2 to hold the question true. SUFF
Ans C
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First of all, i'm assuming that x2 means x^2.radhika1306 wrote:If x(x - 5)(x + 2) = 0, is x negative?
(1) x2 – 7x ≠ 0
(2) x2 –2x –15 ≠ 0
For x(x - 5)(x + 2) = 0, x has to be 0, 5 or -2.
1) It states that x ≠ 0 and x ≠ 7. So x could be 5 or -2. So INSUFF
2) It states that x ≠ 5 and x ≠ -3. So x could be 0 or -2. So INSUFF
Combining 1 & 2, we get that x ≠ 0 and 5. Then x must be -2. So x is negative. Answer is therefore C.
What's the OA?
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