Given that 'a' and 'b' are integers and
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
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1. Insufficientharsh.champ wrote:Given that 'a' and 'b' are integers and
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
Where are these questions from? This is, as ajith points out above, mathematically impossible; it's the second of your questions I've replied to today which has no legitimate solution, and I'm curious to know their source so I can tell my students not to use it. From the stem, we know thatharsh.champ wrote:Given that 'a' and 'b' are integers and
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
_____________________Ian Stewart wrote:Where are these questions from? This is, as ajith points out above, mathematically impossible; it's the second of your questions I've replied to today which has no legitimate solution, and I'm curious to know their source so I can tell my students not to use it. From the stem, we know thatharsh.champ wrote:Given that 'a' and 'b' are integers and
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
-2 < b - 11
9 < b
So Statement 1 tells us nothing we don't already know; it is useless, and the answer must therefore be B or E. Now, since b is an integer greater than 9, with Statement 2 we can be certain that b=10. But there's a problem; now no value of a is possible. We know that -2 < a - 6, so a > 4. But if b = 10, we also have that a-6 < 10-11, so a-6 < -1, and a < 5. That is, we must have that 4 < a < 5. That's not possible if a is an integer. There's no mathematically correct answer to this question.
If a and b are integers and -2 < (a - 6) < (b - 11), then a > 4 and b > 9, just no need of the info that b^2 > 9.harsh.champ wrote:Given that 'a' and 'b' are integers and
-2<(a-6)<(b-11)and
(b^2) > 9 . Find the value of 'b'.
A. b > 9
B. b < 11
-2<(a-6)<(b-11)sanju09 wrote: (2) b < 11, with b an integer greater than 9 only tells, b = 10. Sufficient
It certainly is, my friend. I am in a way supporting Ian's claim by making it a possible question only if we could ignore 'a', which we can't. Whatsoever is the source, it's not a GMAT problem.ajith wrote:-2<(a-6)<(b-11)sanju09 wrote: (2) b < 11, with b an integer greater than 9 only tells, b = 10. Sufficient
If b=10; -2<(an integer)<-1; there exists no such integer! Isn't that a problem?
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