How would you efficiently work through this question?
Is |x - y| > |x| - |y|?
I. y < x
II. xy < 0
Answer is B
Is |x - y| > |x| - |y|?
I. y < x
II. xy < 0
Answer is B
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Frankenstein, Why would you think of squaring both sides of the equation in statement 2?Frankenstein wrote:Hi,
From(2):As xy<0, |xy| = -xy
case-1 : |x| - |y| < 0
As |x - y| > 0, |x - y| > |x| - |y| always holds
case-2 : |x| - |y| > 0
|x - y|^2 = x^2 + y^2 - 2xy = x^2 + y^2 + 2|xy|
(|x| - |y|)^2 = x^2 + y^2 - 2|xy|
So, |x - y|^2 > (|x| - |y|)^2
So, |x - y| > |x| - |y|
Sufficient
B
Hi,ccassel wrote:Frankenstein, Why would you think of squaring both sides of the equation in statement 2?Frankenstein wrote:Hi,
From(2):As xy<0, |xy| = -xy
case-1 : |x| - |y| < 0
As |x - y| > 0, |x - y| > |x| - |y| always holds
case-2 : |x| - |y| > 0
|x - y|^2 = x^2 + y^2 - 2xy = x^2 + y^2 + 2|xy|
(|x| - |y|)^2 = x^2 + y^2 - 2|xy|
So, |x - y|^2 > (|x| - |y|)^2
So, |x - y| > |x| - |y|
Sufficient
B
Thanks,
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