DS - a - b > 0
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shahdevine
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rewrite:Xbond wrote:Hi there,
Could you explain in the simplest this concept and how to resolve it
Is a - b > 0 ?
(1) a(square) = 16
(2) b(square) = 4
is a>b?
s1) a^2=16 --> a=-4 or 4 but we know nothing about b. insufficient.
s2) b^2=4 --> b=-2 or 2 but we know nothing about a.
insufficient
s1+s2) a>b when a=4 and b=2 or -2 however a could equal -4 which would invalidate a>2. In any case, with a and b having a range of values, s1+s2 is insufficient. therefore E.
you got this man!












