DS-17

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Sun Jan 13, 2008 10:47 pm
Thanked: 1 times

DS-17

by desihokie » Fri Jan 18, 2008 12:11 am
powerprep Q
Attachments
DS_17.jpg

Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Thu Jan 17, 2008 11:44 pm

by sachin9c » Fri Jan 18, 2008 1:08 am
Both statements together answer the question. Lets say cost of Mat is X, the cost of Lab would be 2X. Lets assume the profit is marginally above the cost of Lab, approx 2X. X=100.

User avatar
Master | Next Rank: 500 Posts
Posts: 423
Joined: Thu Dec 27, 2007 1:29 am
Location: Hyderabad, India
Thanked: 36 times
Followed by:2 members
GMAT Score:770

by simplyjat » Fri Jan 18, 2008 4:13 am
Basically you have three variables. M (cost of material) , L (cost of labor) and P (profit)....
Form question stem we know M + L + P = 500....
We need two more equations for solve all the three variables....

1. 3M = (M + L + P)
we get another equation but the solution requires one more equation (insufficient)

2. P > L... this ia not an equation but an inequation.... which can have various results...

Combining the two we have two equations and one inequation, and thus can't actually find out the exact values of three variables....

but the answer is but we are asked about the a range in the question...
solving 1 & 2 we come to know that
L+P = 333.33
Now as P > L, which is only possible when
P > 50% of 333.33
=> P > 166.67
=> P > 150

Thus the correct answer is C...
simplyjat

Senior | Next Rank: 100 Posts
Posts: 49
Joined: Sun Jan 13, 2008 10:47 pm
Thanked: 1 times

by desihokie » Fri Jan 18, 2008 8:15 am
i dont get it

1) says that total cost (L+M) = 3M

how did you get 3M = L+M+[b]P[/b]?

Also, you got

"solving 1 & 2 we come to know that
L+P = 333.33
"

how is that? u have inequalitis, how did u calculate values?

Pls explain.

Master | Next Rank: 500 Posts
Posts: 195
Joined: Sun Oct 21, 2007 4:33 am
Thanked: 10 times

by sankruth » Fri Jan 18, 2008 8:51 am
Total Cost >> C
Labour >> L
Material >> M
Profit >> P

C = L+M

L+M+P = 500

St 1
C = 3M
L+M = 3M; L = 2M

3M+P = 500

Not Suff

St2
P>L

Not Suff

Both St
P>L; so P>2M
So, 3M + 2M < 500

5M < 500

M < 100

C = 3M or C <300> 200, so C

Senior | Next Rank: 100 Posts
Posts: 49
Joined: Sun Jan 13, 2008 10:47 pm
Thanked: 1 times

by desihokie » Fri Jan 18, 2008 9:43 am
nice post, sankruth - your answer makes sense.

User avatar
Master | Next Rank: 500 Posts
Posts: 423
Joined: Thu Dec 27, 2007 1:29 am
Location: Hyderabad, India
Thanked: 36 times
Followed by:2 members
GMAT Score:770

by simplyjat » Fri Jan 18, 2008 8:50 pm
1. 3M = (M + L + P)
I require more concentration. This is the second time, here, I have not correctly read the question in the properly... :(

As the the second part...
if we have 3M = (M + L + P) & (M + L + P) = 500...
assume L+P = x and solve for x...
simplyjat