1/5)^m (1/4)^18 = 1/2(10)^35 (1/5^m) (1/2^2)18=1/2(2*5)^35 (1/5^m) (1/2^36)=1/2*2^35*5^35 (1/5^m)=(1/5^35) therefore m=35 Could someone please please please tell me step by step, how to go from here: 1/5^m) (1/2^36)=1/2*2^35*5^35 to here: (1/5^m)=(1/5^35)

cris wrote:1/5)^m (1/4)^18 = 1/2(10)^35 (1/5^m) (1/2^2)18=1/2(2*5)^35 (1/5^m) (1/2^36)=1/2*2^35*5^35 (1/5^m)=(1/5^35) therefore m=35 Could someone please please please tell me step by step, how to go from here: 1/5^m) (1/2^36)=1/2*2^35*5^35 to here: (1/5^m)=(1/5^35) Unless the question was misquoted, the reason you're going crazy is because there is no way to get that solution. (1/5)^m * (1/2)^36 = (1/2) * 2^35 * 5^35 (1/5)^m * (1/2)^36 = 2^34 * 5^35 (1/5)^m = (2^34 * 5^35)/(1/2)^36 (1/5)^m = (2^34 * 5^35) * 2^36 (1/5)^m = 2^70 * 5^35 5^(-m)/5^35 = 2^70 5^(-m-35) = 2^70 As you can see, there is no simple solution for m. If we backsolve with m=35, we get: 5^(-70) = 2^70 which clearly isn't true. Does someone have the source of the question? Something must have been lost or transposed in the translation.

Thank god !! :) Stuart, this question was posted by SALMA, Jan 29 2008 under the title "[b]Powers[/b]"....you can find it easly in the posts if you go a bit downwards.... Someone posted that solution and Slama said that is was ok....and I just couldnt see how... Once again Stuart, thank you

I think the question is (1/5)^m (1/4)^18 = 1/2(10)^35.... m=35 is the answer Suggest me if iam wrong

sibbineni wrote:I think the question is (1/5)^m (1/4)^18 = 1/2(10)^35.... m=35 is the answer Suggest me if iam wrong Is the right side supposed to be: 1/(2*(10^35))? If the whole expression is in the denominator, then the question makes sense. We now have: (1/5)^m * (1/2)^36 = 1/(2 * 2^35 * 5^35) (1/5)^m * (1/2)^36 = 1/(2^36 * 5^35) (1/5)^m * (1/2)^36 = (1/2)^36 * (1/5)^35 Dividing both sides by (1/2)^36, we get: (1/5)^m = (1/5)^35 and therefore m=35