BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

doubt in solving questions in 1000 ps

Expert replies
by shan_shine007 » Wed May 14, 2008 1:12 am
can anyone help in solving the following questions in 1000 ps

section 1 - Qn.5

5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90

section 1 - Qn.13

13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
Last edited by shan_shine007 on Wed May 14, 2008 8:12 pm, edited 1 time in total.
Join the discussion
Source: — Problem Solving |

by aatech » Wed May 14, 2008 7:05 am
h+c = 3.59 ---(1)
h+f = 4.40 ---(2)

f=2c => c=f/2---(3)

Substitute c in (1) from (3)
and solve (1) and (2)

f = 1.62.. Does not look like ans is there..

Are you sure second question is complete? Looks like there is something missing...
Join the discussion

by shan_shine007 » Wed May 14, 2008 8:09 pm
13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
Join the discussion

by bia » Wed May 14, 2008 9:51 pm
There are (20x3)/2 = 30 games that that team played.
In order to win at least 3/4 of all its games , they have to win (3/4)x30 ~ 23 games
So, the greatest number of the remaining games that the team can lose is 30-23 = 7 games

Answer is A
Bia
Join the discussion

by akshatsingh » Wed May 14, 2008 10:38 pm
section 1 - Qn.5

5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90


h+f = 4.40
h+c = 3.59
or
h+2c = 4.40 (since f=2c)
h+c + 3.59

c = 0.81
f = 2c = 1.62



section 1 - Qn.13

13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

I'll just add to what Bia wrote:

There are (20x3)/2 = 30 games that that team played.
In order to win at least 3/4 of all its games , they have to win (3/4)x30 ~ 23 games
So, the greatest number of the remaining games that the team can lose is 30-23 = 7 games

therefore, the greatest number of the "remaining" games that the team can lose = 7 - 3 = 4

Answer is D
Aks
Join the discussion

by shan_shine007 » Wed May 14, 2008 10:42 pm
Giv d soln for dis ...

Month Average Price per Dozen

April $1.26
May $1.20
June $1.08


19. The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If 2/3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
(A) $1.08
(B) $1.10
(C) $1.14
(D) $1.16
(E) $1.18
Join the discussion

by akshatsingh » Wed May 14, 2008 10:51 pm
given on the original thread for this Question

Here it goes again..


A M J
(2/3)X X (4/3)X


Average= {(2/3)X*1.26 + X*1.2 + (4/3)X*1.08}/{(2/3)X+X+(4/3)X}

On solving Average = 1.16

Answer D
Aks
Join the discussion