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zaarathelab
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If y is an integer and y = |x| + x, is y=0?
(1) x < 0
(2) y < 1
I am getting A as the answer whereas the OA is D
Statement 1
x<0
If x less than 0 the |x| + x = 0 (simple logic). This can be proved algebraically as well.
Hence y = 0. sufficient.
Statement 2
y<1
algebraically
case 1
|x| + x <1
x<1-x
x<1/2 - - - -1
case 2
x >- (1 -x) - - -- not possible. Discard
Hence x<1/2
Now x can take 1/3,1/4 value...in that case y<1 , but not 0, but if x=0 then y = 0.
Hence statement 2 is insufficient
Where am I going wrong?
(1) x < 0
(2) y < 1
I am getting A as the answer whereas the OA is D
Statement 1
x<0
If x less than 0 the |x| + x = 0 (simple logic). This can be proved algebraically as well.
Hence y = 0. sufficient.
Statement 2
y<1
algebraically
case 1
|x| + x <1
x<1-x
x<1/2 - - - -1
case 2
x >- (1 -x) - - -- not possible. Discard
Hence x<1/2
Now x can take 1/3,1/4 value...in that case y<1 , but not 0, but if x=0 then y = 0.
Hence statement 2 is insufficient
Where am I going wrong?
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