BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

divisibility and sums

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 139
Joined: Wed May 07, 2008 12:27 pm
Thanked: 8 times
by acecoolan » Sun Nov 09, 2008 8:18 pm
x, y, a, and b are positive integers. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is NOT a possible value for y + b?
24
21
20
17
15
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 2134
Joined: Mon Oct 20, 2008 11:26 pmFollowed by: 25 members
Thanked: 237 times
GMAT Score:730

Re: divisibility and sums

by logitech » Sun Nov 09, 2008 8:40 pm
acecoolan wrote:x, y, a, and b are positive integers. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is NOT a possible value for y + b?
24
21
20
17
15
well, y>6 and b>9 x+y>15 Hence, E

Why y is greater than 6 is your homework. :wink:
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 139
Joined: Wed May 07, 2008 12:27 pm
Thanked: 8 times

by acecoolan » Sun Nov 09, 2008 9:02 pm
well ..logitech. I already know that from the solution to this problem - this is a MGMAT question ... :)

They have followed the same logic that you have but I was hoping to see an alternate soln if at all.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Sun Nov 09, 2008 9:21 pm
acecoolan wrote:well ..logitech. I already know that from the solution to this problem - this is a MGMAT question ... :)

They have followed the same logic that you have but I was hoping to see an alternate soln if at all.
There is no alternate solution

Let me try and justify the same

x/y gives remainder as 6
since division by y is giving a reminder 6 than y has to be greater than 6

try for y less than or equal 6, the remainder can never be 6

so y is 7 8 9 ............


similarly

b will be > 9
b = 9 10 11 12 13.......


min of y+b will be 9+7 = 16
hence
value < 16 is not possible

Hope this helps
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 139
Joined: Wed May 07, 2008 12:27 pm
Thanked: 8 times

by acecoolan » Sun Nov 09, 2008 9:44 pm
Cool. Thanks stop and logitech
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1159
Joined: Wed Apr 16, 2008 10:35 pm
Thanked: 56 times

by raunekk » Sun Nov 09, 2008 10:44 pm
when X/Y the remainder is 6

thus Y has to be greater than 6

Also When A/B the reminder is 9

thus B has to be greater than 9

Thus A+B has to be greater than 9+6=15

Hence E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Mon Nov 10, 2008 6:13 am
Every 6 th number is divisible by 6 (the maximun reminder u can get dividing by 6 is 5) so to get a remainder of 6 y has to be atleast 7. Every 9th number(8 is the maximum remainder u can get dividiing by 9) is divisible by 9 so b has to be alteast 10 which makes the sum 17 (15 cannot be the sum in any case)

E)

Nice problem though...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1