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did any of the players eat a whole pizzza?

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did any of the players eat a whole pizzza?

by uptowngirl92 » Wed Jul 22, 2009 4:04 am
Chanse took his daughter's soccer team for Pizza,1/6 of thh team had exactly 1 slice each,1/6 of thh team had exactly 2 slices each,1/6 of thh team had exactly 3 slices each and the rest had atleast 4 slices each.If a whole pizza consists of 6 slices,did any of the players eat a whole pizzza?

1.there are 12 players on the team.
2.The players ate an avg. of 3 slices per person.

Please give explanations for your answers!
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by shibal » Wed Jul 22, 2009 4:14 am
IMO C
Stmt 1 - 12 players
2pla ate 1
2pla ate 2
2pla ate 3
6pla ate +4.... A large pizza consists of 6 pieces, so they could have eaten exactly 4 pieces or 1 could have eaten more then a whole pizza.... Insuff

Stmt2- not much cuz we don't know how many players we have

1+2 we can see that they eat a total of 36 slices, hence we can see if any player ate a whole pizza

Hope it helps
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by yogami » Wed Jul 22, 2009 9:42 am
IMO its E.
When yo combine both statements we know that 12 slices are eaten by 6 players. The remaining six players should have eaten 36 - 12 = 24 slices amongst them
Now we also know that each player has eaten at least four slices. If you assume that each player eats eactly four slices then none of them has had six slices cos 24 evenly divides into six players into four slices per head. So its insuff
200 or 800. It don't matter no more.
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by shibal » Wed Jul 22, 2009 10:00 am
We are not assuming each eat 4 slices of pizza, it`s given that the rest ate at least 4. If we know that the exact value of pizzas were 36 and that there are 24 slices left to be distributed among 6 players that each eats at least 4 slices, we can know if one ate a whole pizza. IMO C

OA?????
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by vinayakdl » Wed Jul 22, 2009 10:09 am
yogami wrote:IMO its E.
When yo combine both statements we know that 12 slices are eaten by 6 players. The remaining six players should have eaten 36 - 12 = 24 slices amongst them
Now we also know that each player has eaten at least four slices. If you assume that each player eats eactly four slices then none of them has had six slices cos 24 evenly divides into six players into four slices per head. So its insuff
so we can say that none of the players ate entire pizza...i agree with C.

Vinayak
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by mehravikas » Wed Jul 22, 2009 7:49 pm
IMO - C
vinayakdl wrote:
yogami wrote:IMO its E.
When yo combine both statements we know that 12 slices are eaten by 6 players. The remaining six players should have eaten 36 - 12 = 24 slices amongst them
Now we also know that each player has eaten at least four slices. If you assume that each player eats eactly four slices then none of them has had six slices cos 24 evenly divides into six players into four slices per head. So its insuff
so we can say that none of the players ate entire pizza...i agree with C.

Vinayak
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by uptowngirl92 » Thu Jul 23, 2009 1:08 am
Guys!!OA:B..
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another tricky ds

by aimster7888 » Thu Jul 23, 2009 11:25 am
1. Insuff per reason stated above

2.

Let T be the number of players
Number of 1 slice eaters - 1/6T, num. of total 1 slices consumed = 1/6T
Number of 2 slice eaters - same - 1/6T, num of total slices - 1/3T
Number of 3 slice eaters - 1/6T, num of total slices - 1/2T
Remainining players - 1/2T, num total slices = (1/2T)Y, where Y>=4

Average is sum divided by T

( T+(1/2)TY ) / T = 3

= T(1+Y/2) / T = 3
= 1 + Y/2 = 3
= Y/2 = 2
..Y=4

...Sufficient.. B
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