according to if the color of the shirts doesn't matter then 6C6 or simply 6 shirts and not 6!
6! would be if you have one shirt for six kids and distribute this 6! ways or you've got 6 shirts and only one kid you could distribute this 6! by making different in each and every shirt and each and every kid receiving a shirt
here the questions puts down with black on white --> two colors (feel the difference?) three of each color (?) distributed to all kids (?)
first distribute 3 shirts of the same color (say green) and the remaining "undressed" kids should receive other color shirt, hence 6C3=6!/(3!*(6-3)!)=20. Our distribution of one color shirts (three to each ~3~ kids) leaves other three kids expecting different color shirts. In total 20 ways make up our distribution.
jk2010 wrote:Why does the color of the shirts matter? I worked this out to be 6! since there is nothing indicating that the colors of the shirts make a difference. In other words, how many ways can 6 kids get 6 shirts. What am I missing?
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