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Junior | Next Rank: 30 Posts
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Permutation Question!

by Shiram » Wed Aug 25, 2010 11:03 am
Thirty-six identical chairs must be arranged in rows with the same number of chairs each row. Each row must contain at least 3 chairs, and there must be at least 3 rows. A row is parallel to the front of the room. How many different arrangements are possible?

A) 2
B) 4
C) 5
D) 6
E) 10

Thanks to all of you for the help! :)
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by RickH » Wed Aug 25, 2010 11:14 am
What is the correct answer?

My answer would be C, five different arrangements.

I got it this way:

36 (identical chairs) / 3 (at least three rows) = 12
36/4=9
36/6=6
36/9=4
36/12=3

Therefore, 5 different arrangements with at least three row and/or at least three chairs per row.
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Junior | Next Rank: 30 Posts
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by Shiram » Wed Aug 25, 2010 11:36 am
Yes, the answer should be C!

It seems to be so easy, but I was confused when saw that question!... Thanks for your approach! :)
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