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Source: — Problem Solving |

by niraj_a » Fri Aug 29, 2008 3:14 pm
damn dude, where the hell are you getting these ball-bsuter questions from?
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by ddm » Fri Aug 29, 2008 3:33 pm
Manhattan GMAT....suppose to be a 700-800 level question.
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Re: help

by parallel_chase » Fri Aug 29, 2008 3:51 pm
ddm wrote:attachment
sqrt(288xk)


288 = 2*12*12 = 2^5 3^2

x is divisible by 6

least value of x = 6 = 2*3

288x = 2^6*3^3

sqrt(2^6*3^3*k) = 2^3*3 sqrt(3*k) = 24sqrt(3*k)

the question asks what CANNOT be the value of sqrt(288xk)

eliminate A, C, D because every option does have k in the sqrt with one 3.

Option A can and cannot be the value of sqrt(288xk) because we dont know anything about k.

Option E can also be the value of sqrt(288xk), if x=12

Therefore B is answer. Sorry for the typo.

Let me know if you have any doubts.
Last edited by parallel_chase on Fri Aug 29, 2008 4:11 pm, edited 1 time in total.
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by ddm » Fri Aug 29, 2008 4:02 pm
OA-B
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by parallel_chase » Fri Aug 29, 2008 4:11 pm
Sorry for the typo. B is what i meant.
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