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If 56<x<66, where x is an integer. x=?

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If 56<x<66, where x is an integer. x=?

by The Jock » Fri Sep 03, 2010 2:42 am
I am not sure about the source of this question, just saw it somewhere and tried to solve:

If 56<x<66, where x is an integer. x=?

1). When x is divided by 2, the remainder is 1
2). x+1 is divisible by 3.

Stmt 1) When x is divided by 2, the remainder is 1 -> x can be any odd number between 56-66.
such as, 57, 59, 61, 63, 65 so it is Insufficient

Stmt 2) x+1 is divisible by 3 -> x+1 could be 57, 60, 63. SO it is Insufficient
Combining (1) and (2) we get that x can be 59
So answer should be C

Please confirm if I am doing it right, because OA(No official source, so it could be wrong) is different.
Thanks and Regards,
Varun
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by Rahul@gurome » Fri Sep 03, 2010 2:48 am
The Jock wrote:I am not sure about the source of this question, just saw it somewhere and tried to solve:

If 56<x<66, where x is an integer. x=?

1). When x is divided by 2, the remainder is 1
2). x+1 is divisible by 3.

Stmt 1) When x is divided by 2, the remainder is 1 -> x can be any odd number between 56-66.
such as, 57, 59, 61, 63, 65 so it is Insufficient

Stmt 2) x+1 is divisible by 3 -> x+1 could be 57, 60, 63. SO it is Insufficient
Combining (1) and (2) we get that x can be 59
So answer should be C

Please confirm if I am doing it right, because OA(No official source, so it could be wrong) is different.
You are right Varun! The correct answer is (C).
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by The Jock » Fri Sep 03, 2010 3:05 am
Thanks a lot Rahul.
Thanks and Regards,
Varun
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by Rahul@gurome » Fri Sep 03, 2010 3:08 am
The Jock wrote:Thanks a lot Rahul.
You are welcome!
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by sk818020 » Fri Sep 03, 2010 4:14 am
OA is E?

The reason I think so is because;

1) Tells us x must be odd. So x could = 57, 59, 61, 63, or 65. Obviously insufficient.

2) Tells us that x plus 1 is divisible by three. So, x must be 1 less than nubmers divisible by 3. You could also rephrase this to say that when x is divided by three there is a remainder of 1.

The numbers divisible by three close to the range in this set are, 57, 60, 63, 66. Therefore x could equal, 59, 62, 65. Obviously insufficient.

Put them together and X could equal 59, or 65. Thus, together they are insufficient, E.

Is this the answer your book gave you?

THanks,

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by Rahul@gurome » Fri Sep 03, 2010 4:41 am
sk818020 wrote:OA is E?

The reason I think so is because;

1) Tells us x must be odd. So x could = 57, 59, 61, 63, or 65. Obviously insufficient.

2) Tells us that x plus 1 is divisible by three. So, x must be 1 less than nubmers divisible by 3. You could also rephrase this to say that when x is divided by three there is a remainder of 1.

The numbers divisible by three close to the range in this set are, 57, 60, 63, 66. Therefore x could equal, 59, 62, 65. Obviously insufficient.

Put them together and X could equal 59, or 65. Thus, together they are insufficient, E.

Is this the answer your book gave you?

THanks,

Jared
That's a good catch Jared. Possible value of x could also be 65 and then we don't get a unique answer.
The correct answer should be [spoiler](E)[/spoiler].
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by Gurpinder » Fri Sep 03, 2010 8:53 am
The answer is clearly (e).

However, isn't this a bad question though?

Stmt 1 suggests x = odd.
Stmt 2 suggests x = even

Aren't the two statements suppose to be consistent?
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by The Jock » Fri Sep 03, 2010 8:56 am
Yes the given answer is E.
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by sk818020 » Fri Sep 03, 2010 9:01 am
Gurpinder wrote:The answer is clearly (e).

However, isn't this a bad question though?

Stmt 1 suggests x = odd.
Stmt 2 suggests x = even

Aren't the two statements suppose to be consistent?
Statement 1 definetly indicates that x must be an odd number. But statemnt two does not. Statement 2 merely says that if you add 1 to x then it is divisible by 3. For example, 2,5,8,11... Any of those numbers are divisible by 3 if you add 1 to it. In the context of this question, statement 2 indicates that x can be 59,62, or 65. Thus, x could be odd or even.

Hope this helps.

Thanks,

Jared
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by Gurpinder » Fri Sep 03, 2010 9:06 am
sk818020 wrote:
Gurpinder wrote:The answer is clearly (e).

However, isn't this a bad question though?

Stmt 1 suggests x = odd.
Stmt 2 suggests x = even

Aren't the two statements suppose to be consistent?
Statement 1 definetly indicates that x must be an odd number. But statemnt two does not. Statement 2 merely says that if you add 1 to x then it is divisible by 3. For example, 2,5,8,11... Any of those numbers are divisible by 3 if you add 1 to it. In the context of this question, statement 2 indicates that x can be 59,62, or 65. Thus, x could be odd or even.

Hope this helps.

Thanks,

Jared
True!
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
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