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Difficult Math Question #34 - Arithmetic

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by 800guy » Wed Oct 25, 2006 3:30 pm
Two numbers are less than a third number by 30% and 37 % respectively. How much percent is the second number less than the first?

a) 10 % b) 7 % c) 4 % d) 3 %
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by ajith » Wed Oct 25, 2006 11:05 pm
Two numbers are less than a third number by 30% and 37 % respectively. How much percent is the second number less than the first?

a) 10 % b) 7 % c) 4 % d) 3 %

A is the answer ..

say the original no is X
first no: is .7X
second no: is .63X

it is (.7-.63) X/.7 =.1 =10%
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by rajs.kumar » Thu Oct 26, 2006 2:14 am
agree with ajith.
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OA

by 800guy » Fri Oct 27, 2006 3:08 pm
here's the OA:

.7 & .63

diff in %= (.7 - .63)/.7 * 100= .07/.7 * 100= 10%
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please explain

by navdeepbajwa » Tue Oct 20, 2009 1:01 am
I can't understand this part

diff in %= (.7 - .63)/.7 * 100

why we have to divide by 0.7 why can't it be difference * 100 = 7%

thanks
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Re: please explain

by regor60 » Tue Oct 20, 2009 9:12 am
navdeepbajwa wrote:I can't understand this part

diff in %= (.7 - .63)/.7 * 100

why we have to divide by 0.7 why can't it be difference * 100 = 7%

thanks
Keep track of the base.

The difference of 7% is referenced to the "third" number. 10% is the difference referenced to the "first" number, which itself is 70% of the "third" number. The question is asking for the difference referenced to the "first" number.
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