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Difficult Math Question #32 - Sets

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by 800guy » Mon Oct 23, 2006 2:27 pm
A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?
I. –3 II. 1 III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
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by rajs.kumar » Tue Oct 24, 2006 2:55 am
D it is. {-1, 1, 3, ....., +inf}
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by girikoratagere » Tue Oct 24, 2006 7:31 am
Is it C
?
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by ajith » Tue Oct 24, 2006 8:32 pm
D it is ..

since -1 is there 1 has to be there
similarly since 1 is there 3 has to be there
so is 5

-3 may or may not be there...
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by limits660 » Wed Oct 25, 2006 4:27 am
I think its E

All of them are there
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Jeff Sacco
www.jeffsacco.ca
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OA

by 800guy » Wed Oct 25, 2006 3:28 pm
here's the OA:

Series property: t => t+2. (Note: for any given number N, ONLY N + 2 is compulsory. N - 2 is not a necessity as N could be the first term...this can be used as a trap.)
Given: -1 belongs to the series. => 1 => 3 =>5. DOES NOT imply -3.
Hence, II and III (D).
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Re: Difficult Math Question #32 - Sets

by jasminekaur280 » Wed Jun 03, 2020 12:41 am
A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?
I. –3 II. 1 III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
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