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Difficult Math Question #12

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Forum: Difficult Math Question #12

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OA after a few people answer..

The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

A) 20

B) 25

C) 40

D) 45

E) 75

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Junior | Next Rank: 30 Posts Default Avatar
Joined
24 Jun 2006
Posted:
25 messages
Post
5x50 = 45x4 + x
x = 70
Hence range is 70-45=25

Answer is B

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Master | Next Rank: 500 Posts Default Avatar
Joined
27 Jun 2006
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OA:

The answer 25 doesn't refer to a temperature, but rather to a range of temperatures.

The average of the 5 temps is: (a + b + c + d + e) / 5 = 50
One of these temps is 45: (a + b + c + d + 45) / 5 = 50
Solving for the variables: a + b + c + d = 205
In order to find the greatest range of temps, we minimize all temps but one. Remember, though, that 45 is the lowest temp possible, so: 45 + 45 + 45 + d = 205
Solving for the variable: d = 70
70 - 45 = 25

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