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Junior | Next Rank: 30 Posts
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by ankanas » Tue Aug 07, 2007 9:35 pm
Figure ABCD is a rectangle with sides of length x centimeters and width y centimeters, and a diagonal of length z centimeters. What is the measure, in centimeters, of the perimeter of ABCD

(1) x-y= z
(2)z=13

The answer is C :?
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Source: — Data Sufficiency |
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Question

by gmatz » Wed Aug 08, 2007 7:03 am
Did you copy the question correctly? Please check the first statement to see if it is x+y=z. Thanks.
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by gabriel » Wed Aug 08, 2007 7:49 am
@ ankanas .. DS questions go in the DS section ..

@ gmatz .. i have deleted the 2 extra posts that u posted ...

PS : - Welcome to BTG both of you :D ..
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by karthick451 » Wed Aug 08, 2007 10:44 am
Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.
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by bingojohn » Wed Aug 08, 2007 1:36 pm
karthick451 wrote:Looks like there is something wrong with the question. If not, I'm missing something very obvious here.

Since z is the diagonal, it has to be largest side formed by the triangle xyz.

But x-y = z implies that x is greater than z.
Thats right. The question seems wrong. Here is why, mathematically:

x - y = z ...........(a)
x^2 + y^2 = z^2 ...........(b)

squaring both sides of (a), we get:
x^2 + y^2 - 2xy = z^2 .........(c)

subtracting (c) from (b), we get:
2xy = 0

which is impossible, unless ABCD is a line instead of a rectangle.

The explanation provided by some 'guest' above is wrong in more than one places...

The square root of x^2-2xy+y^2 is (x+y) NOPE, its x-y
x^2-2xy+y^2=49 where did you get the 49 from? Thats not a 7, thats a z as in zebra...
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by ankanas » Wed Aug 08, 2007 6:57 pm
Oh...! I forgot to log in when I posted the solution..

Well, I too was not able to figure out how x^2-2xy+y^2=49.. The reason why I posted it here. Looks like the question is wrong...!

Thanks...!

Ankana
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