So possible values of n are 1,2,3 & 6....
Is that fine?
Is that fine?
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n cant be 6,if v don't assume x as 3^4gmatmachoman wrote:So possible values of n are 1,2,3 & 6....
Is that fine?
AM i correct?gmatmachoman wrote:
Soln :
3^4 * 5^6 * 7^3 = (35 ^ n )( x )
case n=6
(V7)^6 . 5^6 .3^4
yes machoman..this is absolutely correct.gmatmachoman wrote:AM i correct?gmatmachoman wrote:
Soln :
3^4 * 5^6 * 7^3 = (35 ^ n )( x )
case n=6
(V7)^6 . 5^6 .3^4
I think if we go with using roots, many numbers would be possible:gmatmachoman wrote:AM i correct?gmatmachoman wrote:
Soln :
3^4 * 5^6 * 7^3 = (35 ^ n )( x )
case n=6
(V7)^6 . 5^6 .3^4
Wow, lots of discussion about this problem!adi_800 wrote:If (3 ^4 )(5 ^ 6 )(7 ^ 3 ) = (35 ^ n )( x ), where x and n are both positive integers, how many different possible values of n are there?
A. 1
B. 2
C. 3
D. 4
E. 6
OA is C
adi_800 wrote:If (3 ^4 )(5 ^ 6 )(7 ^ 3 ) = (35 ^ n )( x ), where x and n are both positive integers, how many different possible values of n are there?
A. 1
B. 2
C. 3
D. 4
E. 6
OA is C