BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

different possible values of n

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 amFollowed by: 2 members
Thanked: 173 times
GMAT Score:710

by gmatmachoman » Sun Jul 25, 2010 2:55 am
So possible values of n are 1,2,3 & 6....

Is that fine?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1460
Joined: Tue Dec 29, 2009 1:28 amFollowed by: 7 members
Thanked: 135 times

by selango » Sun Jul 25, 2010 2:58 am
gmatmachoman wrote:So possible values of n are 1,2,3 & 6....

Is that fine?
n cant be 6,if v don't assume x as 3^4

(3 ^4 )(5 ^ 6 )(7 ^ 3 ) = (5 ^ 6 )(7^6)( 3^4/7^3 )

Note that X must be 3^4/7^3 which is not possible as X is an integer.

So possible values of n are 1,2 and 3,if v don't assume X as 3^4
--Anand--
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 amFollowed by: 2 members
Thanked: 173 times
GMAT Score:710

by gmatmachoman » Sun Jul 25, 2010 3:02 am
gmatmachoman wrote:
Soln :

3^4 * 5^6 * 7^3 = (35 ^ n )( x )


case n=6

(V7)^6 . 5^6 .3^4
AM i correct?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1460
Joined: Tue Dec 29, 2009 1:28 amFollowed by: 7 members
Thanked: 135 times

by selango » Sun Jul 25, 2010 3:06 am
gmatmachoman wrote:
gmatmachoman wrote:
Soln :

3^4 * 5^6 * 7^3 = (35 ^ n )( x )


case n=6

(V7)^6 . 5^6 .3^4
AM i correct?
yes machoman..this is absolutely correct.

The problem is approached in 2 ways.

Taking X as 3^4 and solving for n.[the case u followed,n=2,3,6]

Raising common exponent on both sides and representing other factors as X[the case we followed,n=1,2,3]
--Anand--
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1893
Joined: Sun May 30, 2010 11:48 pmFollowed by: 7 members
Thanked: 215 times

by kvcpk » Sun Jul 25, 2010 3:15 am
gmatmachoman wrote:
gmatmachoman wrote:
Soln :

3^4 * 5^6 * 7^3 = (35 ^ n )( x )


case n=6

(V7)^6 . 5^6 .3^4
AM i correct?
I think if we go with using roots, many numbers would be possible:
(fourthroot(7))^12 * (sqrt(5))^12 * 3^4
12 is also possible.

What you say??
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sun Jul 25, 2010 7:03 am
adi_800 wrote:If (3 ^4 )(5 ^ 6 )(7 ^ 3 ) = (35 ^ n )( x ), where x and n are both positive integers, how many different possible values of n are there?

A. 1
B. 2
C. 3
D. 4
E. 6

OA is C
Wow, lots of discussion about this problem!

3^4 * 5^6 * 7^3 = 5^n * 7^n * x

Since x and n must be positive integers, we can't have more factors of 7 on the right side of the equation than we have on the left side, so largest value of n=3. Since n>0, n = 1, 2, 3.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 809
Joined: Wed Mar 24, 2010 10:10 pmFollowed by: 4 members
Thanked: 50 times

by akhpad » Sun Jul 25, 2010 8:09 am
adi_800 wrote:If (3 ^4 )(5 ^ 6 )(7 ^ 3 ) = (35 ^ n )( x ), where x and n are both positive integers, how many different possible values of n are there?

A. 1
B. 2
C. 3
D. 4
E. 6

OA is C

Govi Bhai

I believe that you must be confused on this problem. This is so easy that you can click without making any calculation.
Here, key is that x and n both are positive integers.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply