suyog: slight mistake in understand the question i think.
3t perimeter of triangle => area = root(3)*(t^2)/4
4s perimeter of square => area = s^2
since areas are equal as per the problem, t:s = 2/(3)^.25
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samirpandeyit62
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I dont think we need to solve for root (root 3) simply we can write it as
(3^1/2)^1/2) = 3^1/4 or 3^.25 which ever way u put it.
(3^1/2)^1/2) = 3^1/4 or 3^.25 which ever way u put it.
Regards
Samir
Samir
3t perimeter of triangle, so side = t
4s perimeter of square, so side = s
As mentioned by agni_mba,
Area of the equilateral triangle is = root(3)*(t^2)/4
and
Area of the Square is = s^2
So, as per the question, the areas are equal,
root(3)*(t^2)/4 = s^2
taking root of both the sides, we get.
3^(1/4) * t / 2 = s
i.e. 3^(1/4) * t = 2s
i.e. t/s = 2 / 3^(1/4)
ratio of t to s is 2 to 3^(1/4).
KO, let us know the ans choices!
4s perimeter of square, so side = s
As mentioned by agni_mba,
Area of the equilateral triangle is = root(3)*(t^2)/4
and
Area of the Square is = s^2
So, as per the question, the areas are equal,
root(3)*(t^2)/4 = s^2
taking root of both the sides, we get.
3^(1/4) * t / 2 = s
i.e. 3^(1/4) * t = 2s
i.e. t/s = 2 / 3^(1/4)
ratio of t to s is 2 to 3^(1/4).
KO, let us know the ans choices!
