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Permutations

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Source: — Problem Solving |

by neelgandham » Fri Nov 18, 2011 2:25 am
Already answered, and done brilliantly by Brent@GMATPrepNow and Saketk https://www.beatthegmat.com/very-tricky- ... 25349.html
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by user123321 » Fri Nov 18, 2011 4:06 am
we need to get all positive integers less than 10000.
=> all integers less than or having four digits.
(n+r-1)C(r-1)
=>8C3 = 56

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