Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
A. 19,000
B. 40,000
C. 100,000
D. 190,000
E. 400,000
The OA is D.
What formulas should I set here in order to solve this PS question? Experts, may you help me? Thanks.
Departments A, B, and C have 10 employees each . . .
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Hi Vincen,
We're told that Departments A, B, and C have 10 employees each, Department D has 20 employees and the Departments have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. We're asked for the number of different task forces that are possible.
With the first 3 Departments, we have (10)(10)(10) = 1,000 possible groups. With Department D though, we have to choose 2 people from 20 total people, so we have to use the Combination Formula:
20!/(2!)(18!) = (20)(19)/(2)(1) = 190
Thus, we have (1,000)(190) = 190,000 possible task forces
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
We're told that Departments A, B, and C have 10 employees each, Department D has 20 employees and the Departments have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. We're asked for the number of different task forces that are possible.
With the first 3 Departments, we have (10)(10)(10) = 1,000 possible groups. With Department D though, we have to choose 2 people from 20 total people, so we have to use the Combination Formula:
20!/(2!)(18!) = (20)(19)/(2)(1) = 190
Thus, we have (1,000)(190) = 190,000 possible task forces
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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The number of ways to select 1 employee from each of departments A, B, and C and 2 employees from department D isVincen wrote:Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
A. 19,000
B. 40,000
C. 100,000
D. 190,000
E. 400,000
The OA is D.
What formulas should I set here in order to solve this PS question? Experts, may you help me? Thanks.
10C1 x 10C1 x 10C1 x 20C2 = 10 x 10 x 10 x (20 x 19)/2 = 10 x 10 x 10 x 10 x 19 = 190,000
Answer: D
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