Is the OA c.6 ??umaa wrote:The number of parallelograms that can be formed from a set of FOUR parallel straight line intersecting a set of THREE parallel straight lines=?
Options are,
a. 9
b. 12
c. 6
d. 18
Amit
no of parallelograms??
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amitdgr
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Ian Stewart
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You're only counting the six smallest parallelograms in the picture (nice picture, by the way!). If, for example, you take all six of the small parallelograms and consider it to be one shape, you get one large parallelogram. And there are many others:
6 parallelograms that measure 1 across, 1 vertical (smallest possible)
3 parallelograms that are 2 across and 1 vertical
4 parallelograms that are 1 across and 2 vertical
2 parallelograms that are 2 across and 2 vertical
2 parallelograms that are 1 across and 3 vertical
1 parallelogram that is 2 across and 3 vertical (all of them together)
Hope the terminology makes sense. That's a total of 18 parallelograms.
6 parallelograms that measure 1 across, 1 vertical (smallest possible)
3 parallelograms that are 2 across and 1 vertical
4 parallelograms that are 1 across and 2 vertical
2 parallelograms that are 2 across and 2 vertical
2 parallelograms that are 1 across and 3 vertical
1 parallelogram that is 2 across and 3 vertical (all of them together)
Hope the terminology makes sense. That's a total of 18 parallelograms.
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amitdgr
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Thanks for explaining it IanIan Stewart wrote:You're only counting the six smallest parallelograms in the picture (nice picture, by the way!). If, for example, you take all six of the small parallelograms and consider it to be one shape, you get one large parallelogram. And there are many others:
6 parallelograms that measure 1 across, 1 vertical (smallest possible)
3 parallelograms that are 2 across and 1 vertical
4 parallelograms that are 1 across and 2 vertical
2 parallelograms that are 2 across and 2 vertical
2 parallelograms that are 1 across and 3 vertical
1 parallelogram that is 2 across and 3 vertical (all of them together)
Hope the terminology makes sense. That's a total of 18 parallelograms.
Ian Stewart wrote: (nice picture, by the way!).
Amit
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cubicle_bound_misfit
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you need to choose 2 parallel lines along with 2 vertical line.
2 parallel lines can be chosen from 4 parallel line in 4C2 ways .
2 vertical lines can be chosen from 3 vertical line in 3C2 ways
together the condition can be chosen in 4C2 * 3C2 ways ==18.
Hope that helps.
Regards,
2 parallel lines can be chosen from 4 parallel line in 4C2 ways .
2 vertical lines can be chosen from 3 vertical line in 3C2 ways
together the condition can be chosen in 4C2 * 3C2 ways ==18.
Hope that helps.
Regards,
Cubicle Bound Misfit
