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girishbtg: Senior | Next Rank: 100 Posts; Posts: 78; Joined: Mon Sep 20, 2010 12:51 am

by girishbtg » Mon Sep 20, 2010 1:21 am

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Source: Beat The GMAT — Problem Solving | Mon Sep 20, 2010 1:21 am

sanju09: GMAT Instructor; Posts: 3650; Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members; Location: India; Thanked: 267 times; GMAT Score:760

by sanju09 » Mon Sep 20, 2010 3:04 am

girishbtg wrote:

We have AB = OC = OB = r, the radius of circle in question. What is âˆ BAO?

â‰¡ âˆ BAO = âˆ BOA = let x =?

âˆ´ âˆ CBO = âˆ BCO = 2 x.

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, we have a linear in x, sufficient

[2] If âˆ BCO = 2 x = 40Âº, then x = 20Âº, sufficient

[spoiler]D[/spoiler]

The mind is everything. What you think you become. -Lord Buddha

Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

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girishbtg: Senior | Next Rank: 100 Posts; Posts: 78; Joined: Mon Sep 20, 2010 12:51 am

by girishbtg » Mon Sep 20, 2010 3:42 am

sanju09 wrote:
girishbtg wrote:

We have AB = OC = OB = r, the radius of circle in question. What is âˆ BAO?

â‰¡ âˆ BAO = âˆ BOA = let x =?

âˆ´ âˆ CBO = âˆ BCO = 2 x.

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, we have a linear in x, sufficient

[2] If âˆ BCO = 2 x = 40Âº, then x = 20Âº, sufficient

[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

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sanju09: GMAT Instructor; Posts: 3650; Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members; Location: India; Thanked: 267 times; GMAT Score:760

by sanju09 » Mon Sep 20, 2010 4:06 am

girishbtg wrote:
sanju09 wrote:
girishbtg wrote:

We have AB = OC = OB = r, the radius of circle in question. What is âˆ BAO?

â‰¡ âˆ BAO = âˆ BOA = let x =?

âˆ´ âˆ CBO = âˆ BCO = 2 x.

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, we have a linear in x, sufficient

[2] If âˆ BCO = 2 x = 40Âº, then x = 20Âº, sufficient

[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, 180Âº - 4 x + x = 120Âº

Or, x = 20Âº. Hence, sufficient

The mind is everything. What you think you become. -Lord Buddha

Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

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girishbtg: Senior | Next Rank: 100 Posts; Posts: 78; Joined: Mon Sep 20, 2010 12:51 am

by girishbtg » Mon Sep 20, 2010 4:14 am

sanju09 wrote:
girishbtg wrote:
sanju09 wrote:
girishbtg wrote:

We have AB = OC = OB = r, the radius of circle in question. What is âˆ BAO?

â‰¡ âˆ BAO = âˆ BOA = let x =?

âˆ´ âˆ CBO = âˆ BCO = 2 x.

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, we have a linear in x, sufficient

[2] If âˆ BCO = 2 x = 40Âº, then x = 20Âº, sufficient

[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If âˆ COD = 60Âº, then âˆ COA = 120Âº

Or, âˆ COB + âˆ BOA = 120Âº

Or, 180Âº - 4 x + x = 120Âº

Or, x = 20Âº. Hence, sufficient

Great...!

Thanks!

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GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Mon Sep 20, 2010 4:18 am

girishbtg wrote:

When you want to see how the angles in a figure affect each other, plug in twice. The attached .pdf shows two sets of angle measurements that satisfy the requirements of the figure. In each case, we can see that COD:BAO = 3:1 and that BCO:BAO = 2:1.

Statement 1:
If COD = 60, then 60:BAO = 3:1, and BAO = 20. Sufficient.

Statement 2:
If BCO = 40, then 40:BAO = 2:1, and BAO = 20. Sufficient.

The correct answer is D.

Attachments

Relationships_between_angles.pdf: (36.41 KiB) Downloaded 92 times

Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
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