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help with combination problem.

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by galaxis09 » Sun Nov 06, 2011 2:50 pm
can someone please help me out with this question.
In how many ways can Ann, Bea, Cam, Don, Ella and Fey be seated if Ann and Bea cannot be seated next to each other?
(A) 240 (B) 360(C) 480(D) 600(E) 720.
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by neelgandham » Sun Nov 06, 2011 3:03 pm
Already answered : https://www.beatthegmat.com/ann-bea-cam- ... 66406.html
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by Anurag@Gurome » Sun Nov 06, 2011 8:10 pm
galaxis09 wrote:can someone please help me out with this question.
In how many ways can Ann, Bea, Cam, Don, Ella and Fey be seated if Ann and Bea cannot be seated next to each other?
(A) 240 (B) 360(C) 480(D) 600(E) 720.
Total ways of seating 6 people = 6!
Consider Ann and Bea as one person, then number of ways of arranging 5 people = 5!
Number of ways of arranging Ann and Ben = 2!
Required number of ways of seating 6 people if Ann and Bea are not seated next to each other = 6! - 5!2! = 720 - 240 = 480

The correct answer is C.
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