D.S.

i think we need some more info to solve this... something missing!

OA=C

Thats all the information they give me

i think i got it!
1) let the length of shorter piece be x, then longer piece will be (x+20)
Total will be 2x+ 20....this is all we get from stmnt 1..insufficient
(2) The length of the shorter piece is 1/3 the length of the longer piece
we get smaller piece as total length/4 & longer length=3(total length)/4 .. this is insufficient
(1)+(2) from (1) we get total length = 2x+20
from (2) we get 1/4 of total length = smaller piece=(2x+20)/4
smaller piece from(1)=x
x=(20+2x)/4
x=10
longer piece =10*2+20=40
answer C

Not a big deal but I think shorter piece is 10 and longer piece 30

Still C)

Ya same Line ! this is a fraction problem ! in the first statement u get the difference in length and connected thru a unknown term x

Second statement u get ! 1/3 which is the relation again bet ween

So we use both we get the length

Straight forward indeed

Vishu

two variables, two equatioons..

vish150783 wrote:two variables, two equatioons..

This rule is, without a doubt, THE most powerful tool for solving data sufficiency questions.

If you understand the "n distinct linear equations for n variables" rule (including all of its subtleties), you will save a TON of time in data sufficieny.

Let's see how quickly we could have solved this question:

Q: Cut a rod into two pieces (we'll call them l and s). How long is l?

(1) l is 20 more than s.

We can make this into one equation, but we have two unknowns: insufficient.

(2) s is 1/3 l.

We can make this into one equation, but we have two unknowns: insufficient.

Together: two distinct linear equations, two unknowns. We can answer ANY question about the system: sufficient.

Together sufficient, apart insufficient: choose (C).

Note that not only did we not solve for l, but we also didn't even bother to translate the equations. Avoiding unnecessary calculations is the key to DS happiness.