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divison and remainder

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divison and remainder

by bfman » Thu Jul 30, 2009 6:55 pm
Q: When 15 is divided by y, the remainder is y-3. If y must be an integer, what are all the possible values of y?

I got 3, 6, and 9.

Book also includes 18. I don't understand how 18 is possible?

15/18 ???
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by raghavsarathy » Thu Jul 30, 2009 8:07 pm
Yup. When 15 is divided by 18 , the remainder would be 15 (18-3).

Hence satisfies the condition.
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by bfman » Thu Jul 30, 2009 8:12 pm
raghavsarathy wrote:Yup. When 15 is divided by 18 , the remainder would be 15 (18-3).

Hence satisfies the condition.
How does this work???

15/18 =

0.8
18 |---------
150
144
------
7 (remainder)
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by bfman » Thu Jul 30, 2009 8:21 pm
raghavsarathy wrote:Yup. When 15 is divided by 18 , the remainder would be 15 (18-3).

Hence satisfies the condition.
That was if the question said 18/15, but the questions says 15/18. and also the remainder has to equal y (denominator) minus 3. So I don't understand how there can be an 18 there as one of the answers.

thanks.
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by scoobydooby » Thu Jul 30, 2009 8:44 pm
bfman wrote:
raghavsarathy wrote:Yup. When 15 is divided by 18 , the remainder would be 15 (18-3).

Hence satisfies the condition.
How does this work???

15/18 =

0.8
18 |---------
150
144
------
7 (remainder)
we must only consider integral quotient, since numerator is less than the denominator, the numerator is the remainder
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by tohellandback » Thu Jul 30, 2009 8:49 pm
yn+y-3=15
y=18/1+n ;y is positive integer >=3
n=0,1,2,5,8,17 give you integer values of y>=3
y=18,6,3
The powers of two are bloody impolite!!
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by bfman » Fri Jul 31, 2009 10:25 am
Thank you folks. I think I understand now. Just need more practice.
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