swerve wrote:Currently, there are 40 cars in each row of the lot at a car dealership. If the parking spaces are to be widened and lengthened so that only 30 cars fit in each row and fewer rows fit in the lot, how many cars will then fit in the entire lot?
1) There will be 3 fewer rows of cars.
2) Currently, there are 10 rows of cars.
The OA is C.
Source: Veritas Prep
Say currently there are x number of rows, thus, 40x cars are parked. Say, after the new arrangement, there are y number of rows such that y < x (given), thus, 30y cars can be parked. We have 40x > 30y => 4x > 3y
We have to get the value of 30y.
Let's take each statement one by one.
1) There will be 3 fewer rows of cars.
=> y = x - 3
Given, 4x > 3y, we have 4x > 3(x - 3) => x > -9. It's not of any use. Insufficient.
2) Currently, there are 10 rows of cars.
x = 10, but we do not know that value of y. Insufficient.
(1) and (2) together
Given x = 10, we have y = 10 - 3 = 7
Thus, the number of cars that can fit now = 30*7 = 210. Sufficient.
The correct answer:
C
Hope this helps!
-Jay
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