Is the answer 10?

I ve seen this problem on this forum already afaik.

1) lets solve this for just one (first quadrant)
in order to make the square with integer sides - we have to know what pairs of (x;y) give us the desired square.
Assume we need to know just one pair of (x;y) coordinates of a square side - let it be OB ( 0 - origin)
- O (0:0),B (10:0)
- O (0:0),B (8:6)
- O (0:0),B (6:8)
SO, in each quadrant there will be 3 different square positions.
==> 12 IMO

the answer is 12, vertices with coordinates:
(-10,0)
(-8,6)
(-6,8)
(0,10)
(6,8)
(8,6)
(10,0)
(8, -6)
(6, -8)
(0, 10)
(-6, -8)
(-8, -6)

There are 12 different ways to draw ab, and so there are 12 ways to draw abcd.