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by El Cucu » Sat Jan 17, 2009 6:02 pm
Hi Guys, I found this problem complex ( I don't have a quant backround) even though I read MGMAT chapter. Any strategy to tackle this will be very appreciate.

* Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that
are (a) parallel to the given line and (b) perpendicular to it.

Especifically I need to understand how to calculate the y intercept of both the parallel and the perpendicular lines (as it is easy to find the slope of both). Also if you have a link explaining the properties in detail will be great! Many tks. in advance...
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by truplayer256 » Sat Jan 17, 2009 6:15 pm
2x-3y=9
y=2x/3-3
Slope of parallel line-2/3
Slope of perpendicular line- -3/2

POINT SLOPE:
y-y1=m(x-x1)

(a.) y+1=2/3(x-4)
y=2x/3-8/3-1-->y=2x/3-11/3

(b.) y+1= -3/2(x-4)
y=-3x/2+6-1-->y=-3x/2+5
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by El Cucu » Sat Jan 17, 2009 6:26 pm
truplayer256 wrote:2x-3y=9
y=2x/3-3
Slope of parallel line-2/3
Slope of perpendicular line- -3/2

POINT SLOPE:
y-y1=m(x-x1)

(a.) y+1=2/3(x-4)
y=2x/3-8/3-1-->y=2x/3-11/3

(b.) y+1= -3/2(x-4)
y=-3x/2+6-1-->y=-3x/2+5
Need to understand the point slope besides applying the equation given, tks.
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