BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Coordinate plane

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 236
Joined: Fri Nov 28, 2008 9:16 am
Thanked: 9 times
by El Cucu » Sat Jan 17, 2009 6:02 pm
Hi Guys, I found this problem complex ( I don't have a quant backround) even though I read MGMAT chapter. Any strategy to tackle this will be very appreciate.

* Given the line 2x – 3y = 9 and the point (4, –1), find lines through the point that
are (a) parallel to the given line and (b) perpendicular to it.

Especifically I need to understand how to calculate the y intercept of both the parallel and the perpendicular lines (as it is easy to find the slope of both). Also if you have a link explaining the properties in detail will be great! Many tks. in advance...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 392
Joined: Thu Jan 15, 2009 12:52 pm
Location: New Jersey
Thanked: 76 times

by truplayer256 » Sat Jan 17, 2009 6:15 pm
2x-3y=9
y=2x/3-3
Slope of parallel line-2/3
Slope of perpendicular line- -3/2

POINT SLOPE:
y-y1=m(x-x1)

(a.) y+1=2/3(x-4)
y=2x/3-8/3-1-->y=2x/3-11/3

(b.) y+1= -3/2(x-4)
y=-3x/2+6-1-->y=-3x/2+5
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 236
Joined: Fri Nov 28, 2008 9:16 am
Thanked: 9 times

by El Cucu » Sat Jan 17, 2009 6:26 pm
truplayer256 wrote:2x-3y=9
y=2x/3-3
Slope of parallel line-2/3
Slope of perpendicular line- -3/2

POINT SLOPE:
y-y1=m(x-x1)

(a.) y+1=2/3(x-4)
y=2x/3-8/3-1-->y=2x/3-11/3

(b.) y+1= -3/2(x-4)
y=-3x/2+6-1-->y=-3x/2+5
Need to understand the point slope besides applying the equation given, tks.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1