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Kaplan daily question bank challenge..is x>y?

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by prachich1987 » Fri Jan 14, 2011 11:18 pm
If x and y are consecutive even integers, is x > y ?

STATEMENT 1:

x - 2 and y + 2 are consecutive even integers.

STATEMENT 2:

x is greater than 2.
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Source: — Data Sufficiency |
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by anshumishra » Fri Jan 14, 2011 11:37 pm
prachich1987 wrote:If x and y are consecutive even integers, is x > y ?

STATEMENT 1:

x - 2 and y + 2 are consecutive even integers.

STATEMENT 2:

x is greater than 2.
If x > y => x = y+2 (so, we need to prove this)


Statement 1:

If (x-2) > (y+2)
=> x-2 = y+2+2
=> x = y+6 (BUT, This impossible as x and y can't be consecutive even number in this case)
so, (x-2) < (y+2), which means :

x-2 + 2 = y+2
=> x = y+2 --- Sufficient

Statement 2:

Not Sufficient

Hence, A
Thanks
Anshu

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by Rahul@gurome » Sat Jan 15, 2011 9:13 am
STATEMENT 1: x - 2 and y + 2 are consecutive even integers.
This implies
  • EITHER (x - 2) = (y + 2) + 2
    • => (x - 2) = (y + 4)
      => x = y + 6
      Therefore, x and y are not consecutive even integers. Hence it is not a valid situation.
    OR (y + 2) = (x - 2) + 2
    • => (y + 2) = x
      It is not valid situation and x > y.
Sufficient

STATEMENT 2: x is greater than 2.
Clearly not sufficient. In case anyone have doubts, consider following examples,
  • 1. x = 4, y = 2 => x > y
    2. x = 4, y = 6 => x < y
Not sufficient

The correct answer is A.
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