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Coordinate geometry

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Coordinate geometry

by roybudhaditya » Fri Oct 05, 2007 11:32 am
In the XY-plane,,line K has positive slope & X-intercept 4.If the area of the triangle formed by line K & the two axes are 12.What is the y-intercept of line K?

a- (-6)
b-(-4)
c-(-3).
d-3
e-6...

How it would be calculate>
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by Suyog » Fri Oct 05, 2007 1:43 pm
Since the area of the triange is given as 12.

Area = h * b / 2
12 = h * 4 / 2 ..... ( X intercept 4)
Solving for h
h = 6

Since the slope of line k is positive we can safely say that y = -6

Point 1 (4,0) and (0,-6)
you can use the formula slope = y1 - y2 / x1 - x2

If we take y as 6 then slope of the line will be negative.

Ans A
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by venmic » Sun Aug 15, 2010 9:20 am
good one
Suyog wrote:Since the area of the triange is given as 12.

Area = h * b / 2
12 = h * 4 / 2 ..... ( X intercept 4)
Solving for h
h = 6

Since the slope of line k is positive we can safely say that y = -6

Point 1 (4,0) and (0,-6)
you can use the formula slope = y1 - y2 / x1 - x2

If we take y as 6 then slope of the line will be negative.

Ans A
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