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Expert replies
Source: — Data Sufficiency |

by tohellandback » Tue Jul 21, 2009 7:15 pm
IMO E
I was wrong..i guess its C
Last edited by tohellandback on Tue Jul 21, 2009 9:39 pm, edited 1 time in total.
The powers of two are bloody impolite!!
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by crackgmat007 » Tue Jul 21, 2009 8:23 pm
can you explain pls?
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by nehakhas1 » Tue Jul 21, 2009 9:00 pm
try to plugin values according to the given options ..if you are getting variable options a/ b is wrong but c is right
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by nehakhas1 » Tue Jul 21, 2009 9:17 pm
try to plugin values according to the given options ..if you are getting variable options a/ b is wrong but c is right
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by tohellandback » Tue Jul 21, 2009 9:40 pm
can someone post the explanation here..
pluggin in numbers is fine but can someone post the algebraic explanation
The powers of two are bloody impolite!!
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by kaulnikhil » Tue Jul 21, 2009 11:18 pm
x/x-y = y-x/2(1+y)

from one :-
x>0>y
from 1 we can conclude that x is positive and y is negative
so we have the orginal equation in the form:-
X(+ ve)
--------------------------------
X(+ve) + Y(as Y negative)

<
-Y -X
---------------------------
2(1 -y)

so y-x
---------
2(1+y)

will result in a positive fraction only when y <-1 hence ..otherwise it wil

result in a negative value hence less than L.H.S
Hence NOT SUFFICIENT
from 2.
y<-1

if X is negative we get X/x-y greater and if xis positive we get y-x/2(1+y)

NOT sufficient

combine both noe u know X is possitive and Y <-1
so RHS will be greater
Hope I make sense
-------
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