IMO C
solving the qn stem
(2-p)(2-q) = 0 ??
4 - 2 (p+q) + pq = 0???
A)
pq given but no infor for p+q
B)
p+q given but no infor for pq
A+B
can solve as both values given
mgmatds4
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stubbornp
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stop@800 wrote:IMO C
solving the qn stem
(2-p)(2-q) = 0 ??
4 - 2 (p+q) + pq = 0???
A)
pq given but no infor for p+q
B)
p+q given but no infor for pq
Awsome use of picking numbers strategy...tnx a lot buddy..
A+B
can solve as both values given
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schumi_gmat
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x^2 - x(p+q) + pq = y
from 1 and 2
To find x intercept y=0
x^2 +2x - 8 = 0
(x+4)(x-2)=0
x=-4 or x =2
HEnce E
from 1 and 2
To find x intercept y=0
x^2 +2x - 8 = 0
(x+4)(x-2)=0
x=-4 or x =2
HEnce E
We do not need to find x intercept, we just need to find that is particulra point valid or not.schumi_gmat wrote:x^2 - x(p+q) + pq = y
from 1 and 2
To find x intercept y=0
x^2 +2x - 8 = 0
(x+4)(x-2)=0
x=-4 or x =2
HEnce E
The equation is quadratic so it can have two x intercepts.
Hope this helps!!
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jimmiejaz
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Dear 4meonly,4meonly wrote:Agree with stop@800
Answer is C - we can answer definetly NO - there is no point (2;0) on this function
I think that the answer is a definite YES. coz when you solve the equation with the 2 values together, we get 0=0;
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venmic
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the below ansers are C and E
I think it is a c because if you solve the values are 2 and -4 so yes it does satisy the equation
so answer should be C
any other explanations please
I think it is a c because if you solve the values are 2 and -4 so yes it does satisy the equation
so answer should be C
any other explanations please
stubbornp wrote:please explain
