y=(-1/6)x + c.
6y = -x + 6c
now find where this line intersects x and why axis.
the points are (0,c) and (6c,0)
draw this on the co-ordinate plane and verify... if c>0 then both x and y are positive,. so when u draw a line passing thru points it passes through the II quadrant. Note that it won't pass through III quadrant.
Try the same for c<0. both x and y intercepts are negative. again it will pass through II quadrant and this time it wont pass through I.
So A is sufficient.
May there is an easier way to do it! But this was the best I could try
