Coordinate + Geometry+ Probability one quest
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Q-> Point (x,y) is a point within the triangle. What is the probability that y<x?
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Is this the complete question ?
Because if a triangle is created in Quadrant 4 , all x > y , and in 1st qudrant 50/50 chances for x > y .. In this 2nd quadrant its 0 probability , Its 50 /50 again if triangle is in 3rd quadrant .
If a traingale always lives within one quadrant , then probability would vary as i explained.
But if a triangle spans across various quadrants its important to know how it co-ordinates would be like . So it can vary dedepnding on more information .
If instead of triangle we would have a circle ,lets say, with centre at origin (0,0) then answer to your question for x> y would be 4/8 = 1/2....
Some body may want to help here
Because if a triangle is created in Quadrant 4 , all x > y , and in 1st qudrant 50/50 chances for x > y .. In this 2nd quadrant its 0 probability , Its 50 /50 again if triangle is in 3rd quadrant .
If a traingale always lives within one quadrant , then probability would vary as i explained.
But if a triangle spans across various quadrants its important to know how it co-ordinates would be like . So it can vary dedepnding on more information .
If instead of triangle we would have a circle ,lets say, with centre at origin (0,0) then answer to your question for x> y would be 4/8 = 1/2....
Some body may want to help here