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Consecutive multiples of 7

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by Ramalakshmi » Sat Jan 15, 2011 10:14 pm
Find the four consecutive multiples of 7 whose sum is 294.



Am getting confused with these kind of problems....(sum of consecutive)

Can anyone give the basic formulas that can be used for this kind of problems.

:(
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by ankur.agrawal » Sat Jan 15, 2011 10:22 pm
Ramalakshmi wrote:Find the four consecutive multiples of 7 whose sum is 294.



Am getting confused with these kind of problems....(sum of consecutive)

Can anyone give the basic formulas that can be used for this kind of problems.

:(
Consecutive Multiples of 7 : 7n, 7n+7, 7n+14, 7n+21 where n is an integer.

Sum= 7n+(7n+7)+(7n+14)+ (7n+21) = 294

N =9. Put the values . the four consecutive multiples are 63 , 70, 77, & 84 which add up to 294.
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by ankur.agrawal » Sat Jan 15, 2011 10:44 pm
Ramalakshmi wrote:Find the four consecutive multiples of 7 whose sum is 294.



Am getting confused with these kind of problems....(sum of consecutive)

Can anyone give the basic formulas that can be used for this kind of problems.

:(
Please go through Consecutive integer chapter in one of manhattan books. Dat shud be sufficient for a good grasp of Consecutive integers.
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by arora007 » Sun Jan 16, 2011 1:48 am
try keep things simple...

x + (x+7)+ (x+14)+ (x+21)

= 4x + 42 =294
4x = 252

x = 63

is the first of the series of 4 multiples of 7
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by GMATGuruNY » Sun Jan 16, 2011 3:42 am
Ramalakshmi wrote:Find the four consecutive multiples of 7 whose sum is 294.



Am getting confused with these kind of problems....(sum of consecutive)

Can anyone give the basic formulas that can be used for this kind of problems.

:(
Here's an easy method:

When numbers are evenly spaced, the average = the median.
Thus, 294/4 ≈ 73 is the median of the 4 consecutive multiples of 7.
The next 2 multiples of 7 larger than 73 = 77 and 84.
The next 2 multiples of 7 smaller than 73 = 63 and 70.
Thus, the four consecutive multiples of 7 whose sum is 294 are:

63, 70, 77, 84.
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by AIM GMAT » Sun Jan 16, 2011 3:58 am
wrote:
Ramalakshmi wrote:Find the four consecutive multiples of 7 whose sum is 294.



Am getting confused with these kind of problems....(sum of consecutive)

Can anyone give the basic formulas that can be used for this kind of problems.

:(
Here's an easy method:
GMATGuruNY
When numbers are evenly spaced, the average = the median.
Thus, 294/4 ≈ 73 is the median of the 4 consecutive multiples of 7.
The next 2 multiples of 7 larger than 73 = 77 and 84.
The next 2 multiples of 7 smaller than 73 = 63 and 70.
Thus, the four consecutive multiples of 7 whose sum is 294 are:

63, 70, 77, 84.

Thanks GMATGuruNY for the super cool method , i just loved it.
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by gmat7202011 » Sun Jan 16, 2011 7:02 am
This is an Arithmetic Progression with

n = number of terms = 4
d = common difference = 7
Sum = 294
a = first number of the progression

Sum = n/2( 2a + (n-1)d)

Solve for a = 63, the rest follow as 70,77 and 84
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