BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

in a game

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 am
Thanked: 85 times
Followed by:3 members

in a game

by clock60 » Sat Nov 20, 2010 10:16 am
hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C

i have little idea how to couple but i am wrong.... where?
if there 24 players, the number of teams and the number of players in every team can be
(4,6) (6,4) (3,8) (8,3)
(1) 24+13=37-1=36-the number of players so possible pairs are
(3,12) (12,3) (6,6) ( 4,9) (9,4) insuff
(2) 24+7=31-1=30 (5,6) (6,5) (3,10) (10,3) again insuff
now i start to understand but not sure
together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff
guys i will be happy to observe other solutions or ways of thinking
Top
Source: — Data Sufficiency |
User avatar
Community Manager
Posts: 991
Joined: Thu Sep 23, 2010 6:19 am
Location: Bangalore, India
Thanked: 146 times
Followed by:24 members

by shovan85 » Sat Nov 20, 2010 10:24 am
clock60 wrote: together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff
You also got E then why did you mention you got C.

From your approach it is clear that there can be 3 teams or 6 teams. Hence we cannot say a concrete answer for total number of teams. So both insufficient.
If the problem is Easy Respect it, if the problem is tough Attack it
Top
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 am
Thanked: 85 times
Followed by:3 members

by clock60 » Sat Nov 20, 2010 10:30 am
hi shovan85
initially i got C, and picked up wrong answer, but while posting the problem i got what is wrong in my reasoning
can you share your way of solving this task?
Top
Legendary Member
Posts: 1337
Joined: Sat Dec 27, 2008 6:29 pm
Thanked: 127 times
Followed by:10 members

by Night reader » Sat Nov 20, 2010 5:44 pm
So luuung...


x=teams, y=players

(2+x)(2+y)=24

st1. (2+x)(2+y+12)=24+12, value for 'y' is positive, 'x' is negative
st2. (2+x)(2+y+6)=24+6, the same here y=22, x=-1

Can not solve for two variables with either statement - E
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
Top
User avatar
Legendary Member
Posts: 866
Joined: Mon Aug 02, 2010 6:46 pm
Location: Gwalior, India
Thanked: 31 times

by goyalsau » Sun Nov 21, 2010 1:41 am
clock60 wrote:hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C
We can have 3 teams , 4 teams , 6 teams 8 teams


3 teams , 4 teams , 6 teams 8 team

8 players , 6 players 4 players 3 players


12 New players can be added in any of the first 3 combinations
as

3 teams
4 players each team

4 teams
3 players each team

6 teams
2 players each team



II statement { 6 players }


3 teams
2 players each team


6 teams
1 players each team

Rest of the possibilities are not possible


So the answer should be E
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.
Top
Legendary Member
Posts: 1119
Joined: Fri May 07, 2010 8:50 am
Thanked: 29 times
Followed by:3 members

by diebeatsthegmat » Sun Nov 21, 2010 8:07 pm
clock60 wrote:hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C

i have little idea how to couple but i am wrong.... where?
if there 24 players, the number of teams and the number of players in every team can be
(4,6) (6,4) (3,8) (8,3)
(1) 24+13=37-1=36-the number of players so possible pairs are
(3,12) (12,3) (6,6) ( 4,9) (9,4) insuff
(2) 24+7=31-1=30 (5,6) (6,5) (3,10) (10,3) again insuff
now i start to understand but not sure
together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff
guys i will be happy to observe other solutions or ways of thinking
i just solved this date logically
to find how many team there are, we have to find how many people for each team
1. 24+13 =33 -1 ( one must sit out of the game) =32
32 can divide into so many team which the number of people are even. For example: 8 teams with 4 people in each or 4 team with 8 peole in each : so insufficient
2/ 24+7 ( the same as 1) in sufficicent
1+2 can tell nothing
Top
Post new topic Post Reply
• Page 1 of 1