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consecutive integers

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by pritam.ryders » Thu Oct 04, 2012 11:42 am
If for 12 consecutive integers with -4 as the least integer ,What is the range of the integers

a:10
b:11
c:6
d:8
e:7
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by das.ashmita » Thu Oct 04, 2012 12:12 pm
Hi Pritam

This question can be done orally

Note down 12 nos starting from -4
-4 -3 -2 -1 0 1 2 3 4 5 6 7

Range = 7 - (-4) =11

ANS B
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by pritam.ryders » Thu Oct 04, 2012 1:01 pm
hey Ashmita ,thanks for the prompt reply..I too thought the answer was 11..but its 6 ..i dont know why nor how..if you could suggest more explanation how its 6 instead of 11..it would be of great help
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by GMATGuruNY » Thu Oct 04, 2012 1:16 pm
Here is the actual question:
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the POSITIVE integers in list K?
For any set of consecutive integers:
Number of integers = biggest - smallest + 1.

Since there are 12 integers, and the smallest = -4, we get:
12 = biggest - (-4) + 1
Biggest = 7.

Thus, the positive integers in List K are 1, 2, 3, 4, 5, 6, 7.
Range = biggest - smallest = 7-1 = 6.
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by sharoonsaleem » Fri Oct 05, 2012 8:04 am
Hi!

I am a bit confused here. Definition of range is the highest value minus the least value, which in this case corresponds to 7-(-4)=11

How come we get to 6??!!
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by mtripathy » Fri Oct 05, 2012 8:22 am
The question is asking the range of POSITIVE integers!!!Usual GMAT style.
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