If (243)^x(463)^y = n, where x and y are positive integers, what is the units digit of n?
(1) x + y = 7
(2) x = 4
(1) x + y = 7
(2) x = 4
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Ans is C!arashyazdiha wrote:If (243)^x(463)^y = n, where x and y are positive integers, what is the units digit of n?
(1) x + y = 7
(2) x = 4
Important aside: The units digit of (243)^x is the same as the units digit of 3^x (since we are only concerned with the last digit, the other digits are of no consequence). Similarly, the units digit of (463)^y is the same as the units digit of 3^y.arashyazdiha wrote:If (243)^x(463)^y = n, where x and y are positive integers, what is the units digit of n?
(1) x + y = 7
(2) x = 4
Statement 1 is'int sufficient because it got 2 variables X and Y , to get to Unit digits of both the numbers we need their respectives powers.akhilsuhag wrote:Prateek I didn't get your question.. are you asking why it can't be C??
Incredible point Brent! very true, somehow my numbmind messup.Brent@GMATPrepNow wrote:Important aside: The units digit of (243)^x is the same as the units digit of 3^x (since we are only concerned with the last digit, the other digits are of no consequence). Similarly, the units digit of (463)^y is the same as the units digit of 3^y.arashyazdiha wrote:If (243)^x(463)^y = n, where x and y are positive integers, what is the units digit of n?
(1) x + y = 7
(2) x = 4
So, we can reword the target question as, "If (3^x)(3^y) = n (where x and y are positive integers), what is the units digit of n?"
Since we now have the two powers (3^x and (3^y) written with the same base, we can combine them to get 3^(x+y)
This means we can further reword the target question as, "If 3^(x+y) = n (where x and y are positive integers), what is the units digit of n?"
Okay, now the statements:
Statement 1: x+y=7
Given this, our target question becomes "What is the units digit of 3^7?"
Since we can answer the target question with certainty, statement 1 is sufficient
Statement 2: x=4
Given this, we are unable to determine the value of 3^(x+y).
So, statement 2 is not sufficient, and the answer is A.
Cheers,
Brent
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