Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Confusing equation - Set11 Q5

Expert replies
by arocks » Sun Oct 07, 2007 11:09 pm
If (y+3)(y-1)-(y-2)(y-1)=r(y-1), what is the value of y?
1) r^2=25
2) r=5

I do not understand why we need to find y at all....Here's my approach...

(y+3)(y-1)-(y-2)(y-1)=r(y-1)
or (y-1)[(y+3)-(y-2)]=r(y-1)
or [(y+3)-(y-2)]=r
or y+3-y+2=r
or 5=r

So ultimately, there is no y. So both the statements are irrelevant.
But can we have a DS question where we do not need to find/prove anything? I may have missed something here, i didn't get the point of this question.

Please explain. Thanks.


OA is E [spoiler][/spoiler]
Join the discussion
Source: — Data Sufficiency |

by samirpandeyit62 » Mon Oct 08, 2007 12:24 am
Hey arocks,
The Q asks "what is the value of y?", and that is what we need to find here, though we can find r without using y.

now

(y+3)(y-1)-(y-2)(y-1)=r(y-1)

stmt 1 :

r^2 =25 so r =-5 or 5

in both cases i.e plugging r=5 or -5 we will end up with a quadratic eqn with y raised to power of 2, hence it will have atleast two solns the two values of r

not suff

stmt 2 :

r =5

again the same case, if we plug in the value of 5 we will get a quadratic eqn of y so it will have two roots so INSUFF

combine: same as stmt 2

so E
Regards
Samir
Join the discussion

by arocks » Mon Oct 08, 2007 12:53 am
Hey thanks....makes sense...but it was a 'different type' of question nevertheless!
Join the discussion