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melon: Senior | Next Rank: 100 Posts; Posts: 34; Joined: Wed Jan 05, 2011 9:15 pmFollowed by: 1 member; Thanked: 3 times

by melon » Sat Jun 25, 2011 1:54 am

what is the median number of employees assigned per project for the projects at company z.
1 25 % of the projects at company z have 4 or more employees assigned to the project.
2 35% of the projects at company Z have 2 or fewer employees assigned to the project.

answer given as C
I saw the explanation
i notice that he assumes the there are 100-(25+35) =40 % project haveing 3 employees ..how did he draw the conclusion that the rest 40% have 3 employees , no where it is given?
I though answer was E.
pls explain[/spoiler]

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Source: Beat The GMAT — Data Sufficiency | Sat Jun 25, 2011 1:54 am

vikram4689: Legendary Member; Posts: 1325; Joined: Sun Nov 01, 2009 6:24 amFollowed by: 14 members; Thanked: 105 times

by vikram4689 » Sat Jun 25, 2011 2:54 am

25% projects have <=2 employees
35% projects have >=4 employees
So rest of 40% of project have to have 3 employees, there is no other possibility. Think over it you will get it:)

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srikanthb.69: Junior | Next Rank: 30 Posts; Posts: 12; Joined: Wed Apr 13, 2011 6:37 am; Thanked: 1 times

by srikanthb.69 » Sat Jun 25, 2011 3:06 am

Any project can have 0 or more number of employees assigned per project.
Statement 1 gives 25%projects have 4 or more employees assigned to them which covers numbers from 4 to any number. - Does not say anything about the remaining 75% projects which can have a significant impact on median - NOT Sufficient
Statement 2 says 35% projects have 2 or less than three employees assigned to them..which covers the numbers from 0 to 2 - Remaining 65% cannot be derived from this so NOT Sufficient
If we combine both the
35% Projects - 0 to 2 employees per project
25% projects - 4 or more employees per project. SO
Remaining 40% - 3 employees per project Hence Median is 3 and ANS is C

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melon: Senior | Next Rank: 100 Posts; Posts: 34; Joined: Wed Jan 05, 2011 9:15 pmFollowed by: 1 member; Thanked: 3 times

by melon » Sat Jun 25, 2011 4:15 am

thanks , i think i got it.

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