Sequence problem

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Sequence problem

by akshatgupta87 » Mon Jan 16, 2012 10:18 am
Q) A sequence of numbers (geometric sequence) is given by the expression: g(n)=5*(-1/2)^n . If the sequence begins with n = 1, what are the first two terms for which |gn - g(n+1)| < 1/1000?

A) g10, g11
B) g11, g12
C) g12, g13
D) g13, g14
E) g14, g15


OA is D

Someone please explain.

~Thanks,
Akshat
Last edited by akshatgupta87 on Mon Jan 16, 2012 11:01 am, edited 1 time in total.
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by neelgandham » Mon Jan 16, 2012 10:59 am
Hey Akshatgupta,

Can you please post the complete question ??
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by akshatgupta87 » Mon Jan 16, 2012 1:04 pm
corrected the question.

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by neelgandham » Mon Jan 16, 2012 1:52 pm
g(n)=5*(-1/2)^n

|gn - g(n+1)| < 1/1000
|5*(-1/2)^n - 5*(-1/2)^(n+1)| < 1/1000
|5*(-1/2)^n (1 - (-1/2))| < 1/1000 (taking 5*(-1/2)^n common from both terms)
|5*(-1/2)^n (3/2))| < 1/1000
|(15/2)*(-1/2)^n| < 1/1000
|(15/2)* ((-1)^n)*((1/2)^n)| < 1/1000
Removing the mod
(15/2)((1/2)^n) < 1/1000
(1/2)^n < 1/7500
2^13 = 8192, 2^12 = 4096
So the minimum value of n, that satisfies the in-equation (1/2)^n < 1/7500 is 13
So, g13 and g14 are the first two terms for which |gn - g(n+1)| < 1/1000.

Option D
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by GMATGuruNY » Mon Jan 16, 2012 1:57 pm
akshatgupta87 wrote:Q) A sequence of numbers (geometric sequence) is given by the expression: g(n)=5*(-1/2)^n . If the sequence begins with n = 1, what are the first two terms for which |gn - g(n+1)| < 1/1000?

A) g10, g11
B) g11, g12
C) g12, g13
D) g13, g14
E) g14, g15


OA is D

Someone please explain.

~Thanks,
Akshat
We can plug in the answers.
It's a good idea to know the powers of 2 up to 2¹�.
2¹� = 1024.
2¹¹ ≈ 2000.
2¹² ≈ 4000.
2¹³ ≈ 8000.
2¹� ≈ 16,000.

Answer choice C: g�₂, g�₃
|g�₃ - g�₂| < 1/1000

|5*(-1/2)¹³ - 5*(-1/2)¹²| < 1/1000

5 * |-1/8000 - 1/4000| < 1/1000

5 * (3/8000) < 1/1000

15/8 < 1.
Doesn't work.
For the left side to DECREASE, the exponents must INCREASE.

Answer choice D: g�₄, g�₃
|g�₄ - g�₃| < 1/1000

|5*(-1/2)¹� - 5*(-1/2)¹³| < 1/1000

5 * |1/16,000 + 1/8000 | < 1/1000

5 * (3/16,000) < 1/1000

15/16 < 1.
Success!

The correct answer is D.
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