BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Company Y employs c women and d men.

Expert replies
by gmat_guy666 » Tue Oct 14, 2014 6:52 am
Company Y employs c women and d men. Do the women at Company Y earn an average (arithmetic mean) annual salary greater than $25,000?

(1) Company Y pays its employees a total of $30,000(c + d) in salaries annually.
(2) The men at Company Y earn an average (arithmetic mean) annual salary of $34,000.


oaE
Join the discussion
Source: — Data Sufficiency |

by [email protected] » Tue Oct 14, 2014 9:52 am
Hi gmat_guy666,

This is a great "concept" question, meaning that you can get most of the way through it without doing too much physical work (as long as you understand the concepts within the question).

We're told that there are C women and D men. We're asked if the women earn an average annual salary > $25,000. This is a YES/NO question.

Fact 1: Total pay for all employees = $30,000(C+D) annually.

This gives us almost no information. Even if we had the values for C and D, we still wouldn't know the average salary for the women.
Fact 1 is INSUFFICIENT.

Fact 2: The men earn an average annual salary of $34,000.

Just like Fact 1, this doesn't give us much information. We know nothing about the number of women or their salaries.
Fact 2 is INSUFFICIENT.

Combined, we know....
Total pay = $30,000(C+D)
Average pay for Men = $34,000

If you're comfortable with the concept behind weighted averages, you might see that this is INSUFFICIENT (as the number of men increases, the average pay for women decreases). Here's how you can prove it though (by TESTing VALUES):

If....
C=1
D=1
Total pay = 30,000(2) = 60,000
Avg. pay for Men = 34,000
Avg. pay for Women = 26,000
The answer to the question is YES

C=1
D=2
Total pay = 30,000(3) = 90,000
Avg. pay for Men = 34,000 x 2 men
Avg. pay for Women = 22,000 x 1 woman
The answer to the question is NO

Combined, INSUFFICIENT

Final Answer: E

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by GMATGuruNY » Tue Oct 14, 2014 11:45 am
gmat_guy666 wrote:Company Y employs c women and d men. Do the women at Company Y earn an average (arithmetic mean) annual salary greater than $25,000?

(1) Company Y pays its employees a total of $30,000(c + d) in salaries annually.
(2) The men at Company Y earn an average (arithmetic mean) annual salary of $34,000.
An alternate way to combine the two statements is to TEST THE THRESHOLD.
Here, the threshold is an average salary of $25,000 for the women.

To test the threshold, we can use ALLIGATION.
For a description of alligation, check my post here:
https://www.beatthegmat.com/mean-t266852.html

Case 1: Average salary for the women = 25,000
Using alligation to determine the ratio of women to men, we get:
W 25,000-----5,000-----30,000-----4,000-----34,000 M
W/M = 4000/5000 = 4/5.
Thus, if there are 4 women for every 5 men, the average salary for the women will be exactly $25,000.

Case 2: Average salary for the women = 29,000
Using alligation to determine the ratio of women to men, we get:
W 29,000-----1,000-----30,000-----4,000-----34,000 M
W/M = 4000/1000 = 4/1.
Thus, if there are 4 women for every 1 man, the average salary for the women will be $29,000.

Since the average salary for the women is EQUAL to $25,000 in Case 1 but GREATER than $25,000 in Case 2, the two statements combined are INSUFFICIENT.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion