BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
i am sure the question shud read like this ...medea66 wrote:How do you solve for this?
What is different from the problem in GMATPrep and the way you wrote it? I think it is the corrected form of the problem.sudhir3127 wrote:i am sure the question shud read like this ...medea66 wrote:How do you solve for this?
2^(x + Y)^2)/2^(x - Y)^2 ... GMAT PREP we dont except this!!!!!!
anyways here we go
2^((x+y)^2 - (x-y)^2)
2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2)
2^(4xy)
2^4*1 = 16..
hope this helps.. i am sure after u see the question in the right way ..its not at all difficult
ur right on 2xy -(-2xy) .. If u see i have already factored in that step and done the calculation...uncbeers wrote:What is different from the problem in GMATPrep and the way you wrote it? I think it is the corrected form of the problem.sudhir3127 wrote:i am sure the question shud read like this ...medea66 wrote:How do you solve for this?
2^(x + Y)^2)/2^(x - Y)^2 ...
anyways here we go
2^((x+y)^2 - (x-y)^2)
2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2)
2^(4xy)
2^4*1 = 16..
hope this helps.. i am sure after u see the question in the right way ..its not at all difficult
Also, shouldn't that second 2xy be a -2xy in [2^(x^2 + 2xy + y^2 - x^2 + 2xy - y^2) ]? That way it is 2^ (2xy - (-2xy)) to become 2^(4xy)?
(x+y)^2 = x^2 + 2xy + y^2
(x-y)^2 = x^2 -2xy + y^2
Hope that is right...
New here Create free account
