Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
This is my approach -
Since order does not matter, I choose combinations
All possible committees = 6C3 = 20
Committees which would have both Michael and Anthony - M, H, 3rd person ; M, H, 4th person ; M, H, 5th person ; M, H, 6th person - 4 committees.
x/100(20) = 4 ====> 20%
But the answer says 40%
could any one please explain...
This is my approach -
Since order does not matter, I choose combinations
All possible committees = 6C3 = 20
Committees which would have both Michael and Anthony - M, H, 3rd person ; M, H, 4th person ; M, H, 5th person ; M, H, 6th person - 4 committees.
x/100(20) = 4 ====> 20%
But the answer says 40%
could any one please explain...
