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by j_shreyans » Sun Apr 26, 2015 4:43 am
If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

If I let c = the number of calendars she usually buys, and p = the dollar value of the standard price of one calendar, I can say that (1.5c) (0.8p) is her total cost at the discounted price.I get (1.5c) (0.8p) = 1.2cp. 120 times the standard price of one calendar is 120p.


Now what should I do after this.

Please help and advise.

Thanks ,

Shreyans
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by GMATGuruNY » Sun Apr 26, 2015 6:08 am
j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140
Let the standard price = $10.

She will be given a 20% discount off the standard price.
Discounted price = 10 - 20% of 10 = $8.

Her total cost would then be 120 times the dollar value of the standard price of one calendar.
Total cost = 120*10 = $1200.

For a total cost of $1200, the number of calendars that can be purchased at the discounted price of $8 = 1200/8 = 150.

A stationery store owner buys 50% more identically-priced calendars than she usually purchases.
Since the 150 calendars purchased at the discounted price represent 50% more than the number usually purchased, the number usually purchased = 100.

The correct answer is C.
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by theCEO » Sun Apr 26, 2015 6:38 am
j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

If I let c = the number of calendars she usually buys, and p = the dollar value of the standard price of one calendar, I can say that (1.5c) (0.8p) is her total cost at the discounted price.I get (1.5c) (0.8p) = 1.2cp. 120 times the standard price of one calendar is 120p.


Now what should I do after this.

Please help and advise.

Thanks ,

Shreyans
Continuing from where you left off..

There are 2 equations for the total cost:
1. The one you calculated : 1.2cp
2. The one given in the question: 120p

setting these 2 equations to equal each other we get
1.2cp = 120p
1.2c = 120
c = 120 / 1.2
c= 100
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by Jeff@TargetTestPrep » Wed Dec 13, 2017 7:06 am
j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140
We can let q = the normal quantity purchased and p = the regular price. Thus:

(1.5q)(0.8p) = 120p

(1.5q)(0.8) = 120

1.2q = 120

q = 120/1.2 = 100

Answer: C

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