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grockit pS

by bblast » Tue May 31, 2011 9:51 am
In the rectangular coordinate system to the left, the line y = -x is the perpendicular bisector of segment RS (not shown) and the y-axis is the perpendicular bisector of segment ST (not shown). If the coordinates of point R are (-3, 1), what are the coordinates of point T ?

(-1, 3)
(-1, -3)
(3, -1)
(1 , 3)
(3, 1)

the figure has nothing but a negative slope line crossing through the origin. NO other points shown

D
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by Frankenstein » Tue May 31, 2011 9:58 am
Hi,
image of a point (p,q) in x+y=0 is (-q,-p) and image of any point (r,s) in Y-axis is (-r,s)
R is (-3,1). So S = (-1,3). Hence, T is (1,3).
So, D

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by bblast » Tue May 31, 2011 10:09 am
https://www.beatthegmat.com/grockit-toug ... tml#335585
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